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27v^2-3=0
a = 27; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·27·(-3)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18}{2*27}=\frac{-18}{54} =-1/3 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18}{2*27}=\frac{18}{54} =1/3 $
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